# Determine the standard form of the equation of the line that passes through (-5,0) and (0,-9).

**Solution:**

The standard equation of a straight line is Ax + By + C = 0.

Equation of the line is (y - y_{1}) = [(y_{2} - y_{1}) / (x_{2} - x_{1})] (x - x_{1}) ------(1)

Given that line passes through (-5, 0) and (0, -9)

∴ Substituting (x_{1}, y_{1}) = (-5, 0) and (x_{2}, y_{2}) = (0, -9) in equation (1),

(y - y_{1}) = [(y_{2} - y_{1}) / (x_{2} - x_{1})] (x - x_{1})

(y - 0) = [(-9 - 0) / (0 - (-5)] [x -(-5)]

y = (-9 / 5) (x + 5)

5y = -9x - 45

9x + 4y + 45 = 0

This is the required equation of the line which is in the general form.

## Determine the standard form of the equation of the line that passes through (-5,0) and (0,-9).

**Summary:**

The standard form of the equation of the line that passes through (-5,0) and (0,-9) is 9x + 4y + 45 = 0.

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